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9x^2+55x-56=0
a = 9; b = 55; c = -56;
Δ = b2-4ac
Δ = 552-4·9·(-56)
Δ = 5041
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5041}=71$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-71}{2*9}=\frac{-126}{18} =-7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+71}{2*9}=\frac{16}{18} =8/9 $
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